Solution

Let the given interior opposite angles be $${(2x)}^{o}$$ and $${(3x)}^{o}$$
We know that an exterior angle of a triangle is equal to the sum of its interior opposite angles.
$$\therefore$$ $$2x+3x={110}^{o}$$
$$5x=110$$
$$x=110/5=22$$
$$\therefore$$ $$\angle A=2x=2=2\times 22={44}^{o}$$
$$\angle B=3x=3\times 22={66}^{o}$$
But $$\angle A+\angle B+\angle C={ 180 }^{ o }$$
$${44}^{o}+{66}^{o}+\angle C={180}^{o}$$
$$110+\angle C={180}^{o}$$
$$\angle C=180-110$$
$$\angle C={70}^{o}$$
$$\angle A={44}^{o}$$, $$\angle B={66}^{o}$$, $$\angle C={70}^{o}$$