Lines and Triangles
In $$\triangle ABC$$, side $$BC$$ has produced to $$D$$. If $$\angle ACD$$ = $$132^{o}$$ and $$\angle BAC$$ = $$54^{o}$$, then $$\angle ABC$$ = ?
In the figure, $$ \angle B=65^o $$ and $$ \angle C = 45^o $$ in $$ \triangle ABC $$ and $$ DAE \parallel BC $$. If $$ \angle DAB = x^o $$ and $$ \angle EAC = y^o $$, find the values of x and y.
Form the question, we have,
$$ \angle B = 65^o , \angle C = 45^o $$, $$ DAE \parallel BC $$
The given lines are parallel,
$$ \angle B = x^o = 65^o $$
[ $$ \because $$ Alternate angles when AB is take as the transversal line]
$$ \angle C = y^o =45^o $$
[ $$ \because $$ Alternate angles when AB is taken as the transversal line]
In $$\triangle ABC$$, side $$BC$$ has produced to $$D$$. If $$\angle ACD$$ = $$132^{o}$$ and $$\angle BAC$$ = $$54^{o}$$, then $$\angle ABC$$ = ?
In $$\triangle ABC$$, side $$BC$$ has been produced to $$D$$. If $$\angle BAC$$ = $$45^{o}$$ and $$\angle ABC$$ = $$55^{o}$$, then $$\angle ACD$$ = ?
In the given figure, side $$BC$$ of $$\triangle ABC$$ is produced to $$D$$ such that $$\angle ABC$$ = $$70^{o}$$ and $$\angle ACD$$ = $$120^{o}$$. Then, $$\angle BAC$$ = ?
In the given figure, $$\angle A$$ = $$50^{o}$$, $$CE \parallel BA$$ and $$\angle ECD$$ = $$60^{o}$$. Then, $$\angle ACB$$ = ?
In the figure given alongside, find the measure of $$\angle ACD$$
In the figure given alongside, find the values of $$x$$ and $$y$$
In the figure given alongside, find the values of $$x$$ and $$y$$
An exterior angle of a triangle measures $${110}^{o}$$ and its interior opposite angles are in the ratio $$2:3$$. Find the angles of the triangle.
If c + g = 140, find k.
If g = 90, what is a + k ?