Solution

$$\text{Molisch}$$ test is for identifying $$\text{carbohydrates.}$$ $$\text{Benedict's test}$$ is for $$\text{aldehydes (not aromatic),}$$ and $$\text{scliwanoff's test}$$ is to $$\text{distinguish ketose from aldose.}$$ aldose doesn't show any positive test. so the organic compound may be an $$\text{aldose(carbohydrate with aldehyde group)}$$

$$\text{Hence, correct answer is Option (D).}$$