Single Choice

Arrange the following in increasing order of number of molecules I. 0.5 mol of $${H}_{2}$$ II. 4.0 g of $${H}_{2}$$ III. 18 g of $${H}_{2}O$$ IV. 2.2 g of $$C{O}_{2}$$

A$$II > III > I > IV$$
B$$IV < I < III < II$$
Correct Answer
C$$I < II < III < IV$$
D$$IV < III < I < II$$

Solution

1 mol of $${H}_{2} = 6.02\times {10}^{23}$$ molecules of $${H}_{2}$$
0.5 mol of $${H}_{2}= 3.01\times {10}^{23}$$ molecules of $${H}_{2}$$
2g of $${H}_{2}= 6.02\times {10}^{23}$$ molecules of $${H}_{2}$$
4g of $${H}_{2}= 12.04\times {10}^{23}$$ molecules of $${H}_{2}$$
18g of $${H}_{2}O= 6.023\times {10}^{23}$$ molecules of $${H}_{2}O$$
44g of $$C{O}_{2}= 6.023\times {10}^{23}$$ molecules of $$C{O}_{2}$$
2.2g of $$C{O}_{2} =\displaystyle\frac{2.2\times 6.023\times {10}^{23}}{44}$$ molecules of $$C{O}_{2}$$
=$$3.01\times {10}^{22}$$ molecules of $$C{O}_{2}$$
Thus required order will be $$IV

SIMILAR QUESTIONS

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