Single Choice

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is $$ 1:4$$. The ratio of number of their molecules is :

A$$ 1:8$$
B$$ 3:16$$
C$$ 1:4$$
D$$ 7:32$$
Correct Answer

Solution

Let,
Mass of $$O_2 = w$$
Mass of $$N_2 = 4w$$
Now,
Molecules of $$ O_{2}=\displaystyle \frac{w}{32\times N_A}$$

Molecules of $$ N_{2}=\displaystyle \frac{4w}{28\times N_A}$$

$$ \displaystyle

\frac{N_{O_{2}}}{N_{N_{2}}}=\displaystyle

\frac{w}{32}\times\displaystyle \frac{28}{4w}=\displaystyle

\frac{7}{32}$$

SIMILAR QUESTIONS

Mole Concept

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Mole Concept

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Mole Concept

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Mole Concept

Which has the maximum number of molecules among the following?

Mole Concept

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Mole Concept

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Mole Concept

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Mole Concept

If $$3$$ moles of ethane $$\displaystyle \left( { C }_{ 2 }{ H }_{ 6 } \right) $$ are given, calculate the following: (i) Number of moles of carbon atoms. (ii) Number of moles of hydrogen atoms. (iii) Number of molecules of ethane.

Mole Concept

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Mole Concept

Which of the following formulae is not correctly depicted?

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