Fluid Mechanics
Pressure head in Bernoulli's equation is:
Bernoulli's equation is conservation of:
Bernoulli's equation : $$ \bigg[ P + \rho gh + \dfrac{1}{2}\rho v^2\bigg] = constant$$
where $$'P' $$ is the pressure energy
$$'\rho gh' $$ is the potential energy per unit volume
$$ \dfrac{1}{2}\rho v^2 $$ is the kinetic energy per unit volume
Thus Bernoulli'e equation implies that the sum of energy is constant and hence is the conservation of energy.
Pressure head in Bernoulli's equation is:
Bernoulli's principle is based on the law of conservation of :
A body weighs $$5\ N$$ in air and $$2\ N$$ when immersed in a liquid. The buoyant force is
Demonstrate that in the case of a steady flow of an ideal fluid $$Eq.(1.7a)$$ turn into Bernoulli equation.
In the case of a fluid, Bernoulli's theorem expresses the application of the principle of conservation of:
The pressure difference across a pipe of length $$5 cm$$ is $$2\times10^{3}Pa$$. Work done by the pressure in forcing $$2m^{3}$$ of water through the pipe in joule is :
The Bernoulli's equation that is valid for non-viscous, incompressible fluids having laminar flow is a consequence of
The velocity of a kerosene oil in a horizontal pipe is $$5 m/s$$. If $$g = 10 m/s^2$$ then the velocity head of oil will be
An ideal fluid flows in the pipe as shown in the figure. The pressure in the fluid at the bottom $${p}_{2}$$ is the same as it is at the top $${p}_{1}$$. If the velocity of the top $${ v }_{ 1 }=m/s$$. Then the ratio of areas $${A}_{1}$$. $${A}_{2}$$ is
State and prove Bernoulli's theorem.