Single Choice

The pressure difference across a pipe of length $$5 cm$$ is $$2\times10^{3}Pa$$. Work done by the pressure in forcing $$2m^{3}$$ of water through the pipe in joule is :

A$$4\times10^{5}$$
B$$2\times10^{5}$$
C$$2\times10^{4}$$
D$$4\times10^{3}$$
Correct Answer

Solution

work done$$=F.d$$
=pressure difference $$\times A\times L=$$pressure diference $$f\times Q$$
$$=2\times 10^{3}\times 2$$
$$=4\times 10^{3}J$$

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