Subjective Type

Convert $$-40^{0}F$$ to the Celsius scale.

Solution

$$F=-40^{0}F$$
Substitute the value of $$F$$ in below equation,
$$\frac{C}{5}=\frac{F-32}{9}$$
$$\frac{C}{5}=\frac{-40-32}{9}$$
$$\frac{C}{5}=\frac{-72}{9}$$
$$\frac{C}{5}=-8$$
$$C=-8*5$$
$$C=-40$$
Solution = $$-40^{0}C$$.

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