Single Choice

Cuprous ion is colourless while cupric ion is coloured because

Acuprous ion has completed d-orbitals, while cupric ion has an incomplete d-orbitals
Correct Answer
Bcuprous ion has exactly half-filled d-orbitals
Ccupric ion has completely filled d-orbitals, while cuprous ion has d-orbitals which are not completely filled.
Dcupric ion has half - filled d-orbitals

Solution

$$Cu^{2+}$$ forms $$[Cu(H_2O)_6]^{2+}$$ complexes. If white light (ordinary sunlight, for example) passes through copper(II), some wavelengths in the light are absorbed by the solution. Copper(II) ions in the solution absorb light in the red region of the spectrum. Hence, it looks blue. The origin of this is d-orbitals being split by the water acting as strong ligands.
$$Cu^+$$ being less charged has a smaller ligand field effect and the transition is in the infrared and does not change our human perceived color.


SIMILAR QUESTIONS

Chemical Bonding

The correct molecular geometry of $$Fe\left ( CO \right )_{5}$$ is: (Z=26 for Fe)

Chemical Bonding

Atomic number of Mn, Fe, and Co are $$25, 26$$, and $$27$$ respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

Chemical Bonding

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is :

Chemical Bonding

A solution of $$[Ni(H_{2}O)_{6}]^{2+}$$ is green but a solution of $$[Ni(CN)_{4}]^{2-}$$ is colourless, Explain.

Chemical Bonding

$$[Fe(CN)_{6}]^{4-}$$ and $$[Fe(H_{2}O)_{6}]^{2+}$$ are of different colours in dilute solutions. Why?

Chemical Bonding

Atomic number of Mn, Fe, and Co are $$25, 26$$, and $$27$$ respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

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