Chemical Bonding
The correct molecular geometry of $$Fe\left ( CO \right )_{5}$$ is: (Z=26 for Fe)
Cuprous ion is colourless while cupric ion is coloured because
$$Cu^{2+}$$ forms $$[Cu(H_2O)_6]^{2+}$$ complexes. If white light (ordinary sunlight, for example) passes through copper(II), some wavelengths in the light are absorbed by the solution. Copper(II) ions in the solution absorb light in the red region of the spectrum. Hence, it looks blue. The origin of this is d-orbitals being split by the water acting as strong ligands.
$$Cu^+$$ being less charged has a smaller ligand field effect and the transition is in the infrared and does not change our human perceived color.
The correct molecular geometry of $$Fe\left ( CO \right )_{5}$$ is: (Z=26 for Fe)
Atomic number of Mn, Fe, and Co are $$25, 26$$, and $$27$$ respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?
The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is :
A solution of $$[Ni(H_{2}O)_{6}]^{2+}$$ is green but a solution of $$[Ni(CN)_{4}]^{2-}$$ is colourless, Explain.
$$[Fe(CN)_{6}]^{4-}$$ and $$[Fe(H_{2}O)_{6}]^{2+}$$ are of different colours in dilute solutions. Why?
Atomic number of Mn, Fe, and Co are $$25, 26$$, and $$27$$ respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?