Single Choice

The correct molecular geometry of $$Fe\left ( CO \right )_{5}$$ is: (Z=26 for Fe)

AOctahedral
BTetrahedral
CSquare pyramidal
DTrigonal bipyramidal
Correct Answer

Solution

Electronic configuration of $$Fe$$ is $$[Ar]3d^64s^2$$. Since, $$CO$$ is a strong field ligand, it will pair the unpaired electrons. Due to high CFSE value, two electrons of 4s orbital will move to 3d orbitals. The five $$CO$$ molecules will then take place in 3d, 4s and 4p gaining $$dsp^3$$ hybridisation.

SIMILAR QUESTIONS

Chemical Bonding

Cuprous ion is colourless while cupric ion is coloured because

Chemical Bonding

Atomic number of Mn, Fe, and Co are $$25, 26$$, and $$27$$ respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

Chemical Bonding

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is :

Chemical Bonding

A solution of $$[Ni(H_{2}O)_{6}]^{2+}$$ is green but a solution of $$[Ni(CN)_{4}]^{2-}$$ is colourless, Explain.

Chemical Bonding

$$[Fe(CN)_{6}]^{4-}$$ and $$[Fe(H_{2}O)_{6}]^{2+}$$ are of different colours in dilute solutions. Why?

Chemical Bonding

Atomic number of Mn, Fe, and Co are $$25, 26$$, and $$27$$ respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

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