Electrochemistry
Conductivity of 0.00241 M acetic acid is $$7.896 \times 10^{-5} S \, cm^{-1}$$. Calculate its molar conductivity. If $$\lambda^o_m$$ for acetic acid is $$390.5 S \, cm^2 \, mol^{-1}$$., what is its degree of dissociation ?
Define the following terms: (i) Fuel cell (ii) Limiting molar conductivity $$\left( { \bigwedge }^{ o }m \right) $$
Fuel cell:- A fuel cell is a device that converts the chemical energy from a fuel into electricity through a chemical reaction. Limiting Molar Conductivity:- Molar conductivity is defined as the conductivity of an electrolyte solution divided by the molar concentration of the electrolyte, and so measures the efficiency with which a given electrolyte conducts electricity in solution. It is the conducting power of all the ions produced by dissolving one mole of an electrolyte in solution.
Conductivity of 0.00241 M acetic acid is $$7.896 \times 10^{-5} S \, cm^{-1}$$. Calculate its molar conductivity. If $$\lambda^o_m$$ for acetic acid is $$390.5 S \, cm^2 \, mol^{-1}$$., what is its degree of dissociation ?
Equivalent conductance of NaCI, HCI and $$CH_{3}COONa$$ at infinite dilution are 126.45, 425.16 and $$91 ohm^{-1}cm^{2}$$4 respectively. What would be the equivalent conductance of $$CH_{3}COOH$$ at infinite dilution?
Answer the following questions : Define limiting molar conductivity . Why conductivity of an electrolyte solution decreases with decrease in concentration ?
The following curve is obtained when molar conductivity $$ ( \Lambda_m) $$ is plotted against the square root of concentration $$ c^{1/2} $$ for two electrolytes A and B. As seen from the graph , the value of limiting molar conductivity $$ (\Lambda^{\circ}_{m}) $$ for electrolyte B cannot be obtained graphically . How can this value be obtained ?