Subjective Type

Equivalent conductance of NaCI, HCI and $$CH_{3}COONa$$ at infinite dilution are 126.45, 425.16 and $$91 ohm^{-1}cm^{2}$$4 respectively. What would be the equivalent conductance of $$CH_{3}COOH$$ at infinite dilution?

Solution

$$CH_3COONA + HCl \rightleftharpoons NaCl + CH_3COOH$$
At infinite dilution,
let equivalent conduction be $$\lambda$$
then
$$\lambda CH_3COONa+ \lambda HCl = \lambda NaCl + \lambda CH_3COOH$$
$$425.16 + 91 = 126.45 + \lambda CH_3COOH$$
$$\lambda CH_3COOH = 425.16 + 91 - 126.45\, ohm^{-1}cm^2$$
$$= 389.71 ohm^{-1}cm^2$$

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