Single Choice

Ejection of the photoelectron from metal in the photoelectric effect experiment can be stopped by applying $$0.5\ V$$ when the radiation of $$250\ nm$$ is used. The work function of the metal is:

A$$5.5\ eV$$
B$$4\ eV$$
C$$5\ eV$$
D$$4.5\ eV$$
Correct Answer

Solution

From Ejection photoelectron
$$\because hv = hv_o + K.E.$$
$$\dfrac{hv}{x} = \phi+\text{Stopping pot}$$
$$\therefore \phi = \dfrac{hc}{x} - S.P.$$

$$=\dfrac{6.6\times 10^{-34} \times 3\times 10^8}{250\times 10^{-9}\times 1.6\times 10^{-19}}-0.5\times 1.6\times 10^{-10}$$

$$=\dfrac{6.6\times 3}{250\times 1.6} \times 10^2-0.5$$

$$=4.95 - 0.5$$
$$\sim 4.5 eV$$

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