Single Choice

The highest energy in Balmer series, in the emission spectra of hydrogen is represented by: $$\left({R}_{H}=109737 {cm}^{-1}\right)$$

A$$4389.48 {cm}^{-1}$$
B$$2194.74 {cm}^{-1}$$
C$$5486.85 {cm}^{-1}$$
D$$27434.25 {cm}^{-1}$$
Correct Answer

Solution

$$\bar{v}=\dfrac{1}{\lambda}=R_H{Z}^{2}\left[\dfrac{1}{{n}_{1}^{2}} - \dfrac{1}{{n}_{2}^{2}}\right]$$

$$=109737 \times {1}^{2} \left[\dfrac{1}{{2}^{2}} - \dfrac{1}{{\infty}^{2}}\right] = 27434.25 {cm}^{-1}$$

(series limit will be of highest energy)

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