Subjective Type

Energy of an electron in the ground state of the hydrogen atom is $$-2.18\displaystyle \times 10^{-18}J$$. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol$$\displaystyle ^{-1}$$.

Solution

The ionization enthalpy is the amount of energy required to remove an electron from ground state to infinity. The energy of electron in the ground state is $$\displaystyle -2.18 \times 10^{-18} J $$.
The energy of electron at infity is zero.

The energy required to remove electron is $$\displaystyle 0-(-21.8 \times 10^{-18} J )= 2.18 \times 10^{-18} J $$.

To remove 1 mole of electrons, the amount of energy required is $$\displaystyle 2.18\times 10^{-18} \times 6.023\times 10^{23} = 13.130\times 10^{5} J/mol $$. This is the ionization enthalpy of hydrogen.


SIMILAR QUESTIONS

Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

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Periodic Classification of Elements

Which of the following elements will have highest ionisation energy?

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