Periodic Classification of Elements
Green house effect is caused by :
Which of the following can most easily form unipositive gaseous ion?
The element with electronic configuration $$1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{1}$$ can most easily form unipositive gaseous ion.
$$1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{1}$$ readily loses an electron to form $$1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{0}$$ which is stable electronic configuration as $$3p$$ subshell is empty and $$3s$$ subshell is completely filled.
Green house effect is caused by :
Ionization energy of gaseous $$Na$$ atoms is $$495.5$$ kJ mol$$^{-1}$$. The lowest possible frequency of light that ionizes a sodium atom is: $$[h=6.626\times 10^{-34} \ Js, N_A=6.022\times 10^{23} \ mol^{-1}]$$
For the second period elements the correct increasing order of first ionisation enthalpy is:
Ionizing radiation is:
Energy of an electron in the ground state of the hydrogen atom is $$-2.18\displaystyle \times 10^{-18}J$$. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol$$\displaystyle ^{-1}$$.
Would you expect the first ionization enthalpies for two isotopes of the same element to be the same or different? Justify your answer.
Beryllium has higher ionization enthalpy than boron. This can be explained as :
Ionization enthalpies of transition metals are:
The electronic states $$X$$ and $$Y$$ of an atom are depeicted below: $$X : 1s^{2} 2s^{2} 2p^{6} 3s^{1}$$ $$Y: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{1}$$ Which of the following statements is not correct?
Which of the following elements will have highest ionisation energy?