Subjective Type

Find the ratio of the total number of electron(s) in bonding molecular orbital of $$O_2$$ to the total number of electrons in bonding molecular orbital of $$N_2$$ molecule.

Solution

The total number of electron(s) in bonding molecular orbital of $$O_2$$ is $$10$$.
The total number of electrons in bonding molecular orbital of $$N_2$$ is $$10$$.
Thus, the ratio of the total number of electron(s) in bonding molecular orbital of $$O_2$$ to the total number of electrons in bonding molecular orbital of $$N_2$$ molecule is $$1$$.

SIMILAR QUESTIONS

Chemical Bonding

The most electronegative element is:

Chemical Bonding

The number of antibonding electron pairs in $$O^{2-}_{2}$$ molecular ion on the basis of molecular orbital theory is :

Chemical Bonding

Which of the following species are paramagnetic?

Chemical Bonding

Among $$KO_2, AlO_2^-, BaO_2, and NO_2^+$$, unpaired electron is present in:

Chemical Bonding

The total number of bonding and antibonding electrons in $$\displaystyle O{_{2}}^{+}$$ are respectively. (If the answer is 14 and 7, then represent as 0147):

Chemical Bonding

State True or False. $$O_2, O_2^-$$ and $$O_2^{2-}$$ are paramagnetic species.

Chemical Bonding

Which of the following molecules is expected to exhibit diamagnetic behaviour?

Chemical Bonding

The pairs of species of oxygen and their magnetic behaviours are noted below. Which of the following presents the correct description ?

Chemical Bonding

Which of the following is paramagnetic?

Chemical Bonding

During change of $${O}_{2}$$ to $${O}_{2}^{-}$$ ion, the electron adds on which one of the following orbitals?

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