Atomic Structure
Calculate the wavelength associated with an electron moving with a velocity of $${ 10 }^{ 10 } cm$$ per sec.
For given energy of photon, $$E=3.03\times 10^{-19}J$$ corresponding wavelength will be: $$(h=6.6\times { 10 }^{ -34} sec$$, $$C=3\times { 10 }^{ 8 }m/sec.)$$
$$E=3.03\times 10^{-19} J$$
First we use is:
$$\lambda=\dfrac{hc}{E}$$
$$=\cfrac{6.6\times10^{-34}\times3\times10^{8}}{3.03\times10^{-19}}m$$
$$=656\quad nm$$
Therfore we will get the corresponding wavelength.
Calculate the wavelength associated with an electron moving with a velocity of $${ 10 }^{ 10 } cm$$ per sec.
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