Atomic Structure
For given energy of photon, $$E=3.03\times 10^{-19}J$$ corresponding wavelength will be: $$(h=6.6\times { 10 }^{ -34} sec$$, $$C=3\times { 10 }^{ 8 }m/sec.)$$
The energy of a photon is given as $$3.03\times 10^{-19}$$ J/atom. The wavelength of the photon is :
Energy of photon, $$E=hc/\lambda$$ or $$\lambda=hc/E$$
Where, $$h=6.626 \times 10^{−34}Js, c=3 \times 10^{8}ms^{-1}$$
Given $$E=3.03 \times 10^{−19}J/atom$$
By putting all these values, we get-
$$\lambda=6.626\times 10^{−34}\times 3\times 10^8 /(3.03\times 10^{−19})$$
$$\lambda= 6.56\times 10^{−7}m= 656 nm$$
So, option $$D$$ is correct.
For given energy of photon, $$E=3.03\times 10^{-19}J$$ corresponding wavelength will be: $$(h=6.6\times { 10 }^{ -34} sec$$, $$C=3\times { 10 }^{ 8 }m/sec.)$$
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What should be the mass of the photon of sodium if its wavelength is $$5894 \mathring { A }$$. The velocity of light is $$3\times { 10 }^{ 8 }\ { metre }/{ second }$$ and the value of h is $$6.6252 \times { 10 }^{ -34 } kg\ { { m }^{ 2 } }/{ s\ }?$$
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