Solution

$$He_2$$ has MO electronic configuration as $$\underset {bonding}{\sigma1s^2}\ \underset{Anti-bonding}{{\sigma}^*1s^2}$$ Bond order $$=\cfrac{N_B-N_A}{2}= (2-2)/2=0$$ Thus, electron and Bond − But $$He^+$$ ion exists, as it has a configuration of $$\underset {bonding}{\sigma1s^2}\ \underset{Anti-bonding}{{\sigma}^*1s^1}$$ Bond order $$=\cfrac{N_B-N_A}{2}=\cfrac{2-1}{2}$$ As bond order is positive $$He^+$$ exists. Due to one unpaired electron $$He_2^+$$ is paramagnetic. The statement is true.