Single Choice

The correct order of bond dissociation energy among $$N_2,\ O_2,\ O_2^-$$ is shown in which of the following arrangements?

A$$N_2 > {O}_2^- > O_2$$
B$$O_2 > {O}_2^- > N_2$$
C$$N_2 > O_2 > {O}_2^-$$
Correct Answer
D$${O}_2^- > O_2 > N_2$$

Solution

$$N_2$$ has bond order = 3
$$O_2$$ has bond order=2
$$O_2^-$$ has bond order = 1.5
As bond dissociation energy $$\propto$$ bond order
Thus order of bond dissociation energy is: $$N_2>O_2 > O_2^-$$

SIMILAR QUESTIONS

Chemical Bonding

Which of the following does not exist?

Chemical Bonding

The bond order of $$NO$$ is $$2.5$$ while that of $$NO^{+}$$ is $$3$$. Which of the following statements is true for these two species?

Chemical Bonding

Which of the following pairs have identical values of bond order?

Chemical Bonding

"$$He_2$$ does not exist since its bond-order is zero." Answer whether the above statement is true or false.

Chemical Bonding

Bond order of $$O_2, O_2^+, O_2^-$$ and $$O_2^{2-}$$ is in order________.

Chemical Bonding

The bond order and the magnetic characteristics of $$\text {CN}^-$$ are:

Chemical Bonding

Using MO theory, predict which of the following species has the shortest bond length?

Chemical Bonding

Among the following molecules/ions, $$C^{2-}_2, N^{2-}_2, O^{2-}_2, O_2$$ which one is diamagnetic and has the shortest bond length?

Chemical Bonding

Among the following, the molecule expected to be stabilized by anion formation is: $${C}_{2},{O}_{2},NO,{F}_{2}$$

Chemical Bonding

During the change of $$O_2$$ to $$O_2^-$$, the incoming electrons goes to the orbital:

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