If $$ \eta $$ represents the coefficient of viscosity and $$T$$ the surface tension, then the dimension of $$ \dfrac{T}{\eta} $$ is same as that of :
$$T= \dfrac{F}{L}$$ Surface tension is force per unit length
$$F = \eta A\dfrac{dV}{dx}$$
$$[\dfrac{T}{\eta}]=[LT^{-1}]=[v]$$
When a solid sphere moves through a liquid the liquid opposes is the motion with a force the magnitude of the force depends upon the coefficient of viscosity of the liquid the radius of the sphere find the expression of force using dimension formula:
A horizontal plate ($$10 cm\times 10 cm$$) moves on a layer of oil of thickness $$4$$ mm with constant speed of $$10$$ cm/s. The coefficient of viscosity of oil is $$4$$ poise. The tangential force applied on the plate to maintain the constant speed of the plate is?
The coefficient of viscosity for hot air is
The tangential forces per unit area of the liquid layer required to maintain unit velocity gradient is known as:
The dimensional formula for viscosity is $$[ML^{-1}T^{-1}]$$. One poise, i.e, C.G.S. unit of viscosity is:
A sliding fit cylindrical body of mass of 1 kg drops vertically down at a constant velocity of 5 cm $$s^{-1}.$$ Find the viscosity of the oil.