The tangential forces per unit area of the liquid layer required to maintain unit velocity gradient is known as:
By definition of Tangential force which is equal to the product of coefficient of viscosity, velocity gradient and area.
i.e $$ F_T = \eta A \dfrac{dV}{dX} $$
So, $$\dfrac{F_T}{A} = \eta(1) $$
Therefore, the tangential force per unit area of the liquid layer required to maintain unit velocity gradient is known as Coefficient of viscosity of the liquid.
When a solid sphere moves through a liquid the liquid opposes is the motion with a force the magnitude of the force depends upon the coefficient of viscosity of the liquid the radius of the sphere find the expression of force using dimension formula:
A horizontal plate ($$10 cm\times 10 cm$$) moves on a layer of oil of thickness $$4$$ mm with constant speed of $$10$$ cm/s. The coefficient of viscosity of oil is $$4$$ poise. The tangential force applied on the plate to maintain the constant speed of the plate is?
The coefficient of viscosity for hot air is
If $$ \eta $$ represents the coefficient of viscosity and $$T$$ the surface tension, then the dimension of $$ \dfrac{T}{\eta} $$ is same as that of :
The dimensional formula for viscosity is $$[ML^{-1}T^{-1}]$$. One poise, i.e, C.G.S. unit of viscosity is:
A sliding fit cylindrical body of mass of 1 kg drops vertically down at a constant velocity of 5 cm $$s^{-1}.$$ Find the viscosity of the oil.