Multiple Choice

If α is a complex constant such that az2+z+ ˉ α =0 has a real root then

A$$\displaystyle\ \alpha+\bar{\alpha}=1$$
Correct Answer
B$$\displaystyle\ \alpha+\bar{\alpha}=0$$
C$$\displaystyle\ \alpha+\bar{\alpha}=-1$$
Correct Answer
Dthe absolute value of the real root is 1
Correct Answer

Solution

αz2+z+
ˉ
α
=0

Let x be the real root.
⇒x=
ˉ
x

αx2+x+
ˉ
α
=0 ...(1)

Conjugating equation (1) we get,
ˉ
α

ˉ
x
2+
ˉ
x
+α=0

ˉ
α

ˉ
x
2+
ˉ
x
+α=0 ...(2)

Subtracting eq. (1) & eq. (2) we get,
x2=1⟹x=±1∴|x|=1

Multiplying eq. (1) by
ˉ
α
and eq. (2) by α and then subtracting we get,
x=−(α+
ˉ
α
)=±1

Ans: A,C &D


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