If the balance point is obtained at the $$35^{th} cm$$ in a metre bridge the resistances in the left and right gaps are in the ratio of
Given:
Balance point is obtained at 35 cm in a meter bridge .
Metre Bridge is a device which works on the principle of Balanced Wheatstone Bridge. It helps us to calculate the resistance of an unknown resistor in presence of a known shunt resistance.
It consists of the following parts :
Unknown Resistance
Shunt Resistance
1 metre or 100 cm long wire
Since balance point is obtained at 35 cm , we can consider Balanced Wheatstone Bridge condition such that the adjacent resistances will be in ratio.
Let the resistances be $$P$$ and $$Q$$ and $$l$$ be the balance point :
$$\dfrac{P}{Q} = \dfrac{l}{100 - l}$$
$$\dfrac{P}{Q} = \dfrac{35}{100 - 35}$$
$$\dfrac{P}{Q} = \dfrac{35}{65} \Rightarrow \dfrac{7}{13}$$
So the resistances will be in the ratio of : $$7 : 13$$
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