Current Electricity
In a meter bridge experiment $$S$$ is a standard resistance. $$R$$ is a resistance wire. It is found that balancing length is $$l=25\ cm$$. If $$R$$ is replaced by a wire of half length and half diameter that of $$R$$ of same material, then the balancing distance $$l'$$ (in $$cm$$) will now be--------.
Current Electricity
Let $$\vec{a},\vec{b}$$ and $$\vec{c}$$ be three vectors such that $$|\vec{a}|=\sqrt{3},|\vec{b}|=5,\vec{b}.\vec{c}=10$$ and the angle between $$\vec{b}$$ and $$\vec{c}$$ is $$\dfrac{\pi}{3}$$. If $$\vec{a}$$ is perpendicular to the vector $$\vec{b}\times \vec{c}$$, then $$|\vec{a}\times (\vec{b}\times \vec{c})|$$ is equal to
Current Electricity
A resistance wire connected in the left gap of a metre bridge balances a $$10\Omega$$ resistance in the right gap at a point which divides the bridge wire in the ratio $$3 : 2$$. If the length of the resistance wire is $$1.5 m$$, then the length of $$1 \Omega$$ of the resistance wire is :
Current Electricity
In a meter bridge, the balancing length from the left end (standard resistance of one ohm in the right gap) is found to be $$20 \ cm$$. The value of the unknown resistance is
Current Electricity
If the balance point is obtained at the $$35^{th} cm$$ in a metre bridge the resistances in the left and right gaps are in the ratio of
Current Electricity
In the shown arrangement of the experiment of meterbridge, if AC corresponding to null deflection of galvanometer is x , what would be its value if the radius of the wire AB is doubled
Current Electricity
Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio $$2:3$$. If each resistance is increased by $$3 \Omega$$, the null point divides the wire in the ratio $$5:6$$, calculate the value of X and Y.
Current Electricity
In a meter bridge shown in the figure, the balance point is found to be 40 cm from and A.If a resistance of $$10 \Omega$$ is connected in series with R, balance point is obtained 60 cm from A.Calculate the value of R and S.