Single Choice

If the observed and theoretical molecular mass of NaCl is found to be 31.80 and 58.50, then the degree of dissociation of NaCl is:

A0.8396
Correct Answer
B0.0839
C0.9
D1

Solution

$$i=\cfrac{58.50}{30.80}= 1.8396$$

$$α=\cfrac{i−1}{m−1}=\cfrac{1.8396−1}{2−1}$$

$$= 0.8396$$ or $$83.96$$ %

Hence, the correct option is $$A$$

SIMILAR QUESTIONS

Solutions

A compound $$MX_{2}$$ has observed and normal molar masses 65.6 and 164 respectively. The apparent degree of ionization of $$MX_{2}$$ is:

Solutions

A weak electrolyte $$(AB_2)$$ with formula mass 100 g / mole is dissociated in water upto 50%. The observed molar mass of the electrolyte is:

Solutions

The molecular weight of benzoic acid in benzene as determined by depression in the freezing point method corresponds to:

Solutions

0.0852 g of an organic halide (A) when dissolved in 2.0 g of camphor, the melting point of the mixture was found to be $$167^{\circ}$$C. Compound (A) when heated with sodium gives a gas (B). 280 mL of gas (B) at STP weighs 0.375g. What would be 'A' in the whole process? $$K_f$$ for camphor = 40, m.pt. of camphor = $$179^{\circ}$$C.

Solutions

When a liquid that is immiscible with water was steam distilled at $${\text{95}}{\text{.}}{{\text{2}}^{\text{o}}}{\text{C}}$$ at a total pressure of 748 torr, the distillate contained 1.25 g of the liquid per gram of water. The vapour pressure of water is 648 torr at $${\text{95}}{\text{.}}{{\text{2}}^{\text{o}}}{\text{C}}$$, What is the molar mass of liquid?

Solutions

Acetic acid dissolved in benzene shows a molecular weight of:

Solutions

Benzoic acid dissolved in benzene will show a molecular mass of:

Solutions

Boiling point of chloroform was raised by $$0.323 K$$, when $$0.5143 g$$ of anthracene was dissolved in $$35 g$$ of chloroform. Molecular mass of anthracene is $$\left( {{K_b}\,for\,CHC{l_3} = 3.9\,K\,\,kg\,mo{l^{ - 1}}} \right)$$

Solutions

Molecules of ethanoic acid dimerises in benzene due to $$H-$$bonding if all molecules of ethanoic acid associated in benzene then:

Contact Details