Single Choice

When a liquid that is immiscible with water was steam distilled at $${\text{95}}{\text{.}}{{\text{2}}^{\text{o}}}{\text{C}}$$ at a total pressure of 748 torr, the distillate contained 1.25 g of the liquid per gram of water. The vapour pressure of water is 648 torr at $${\text{95}}{\text{.}}{{\text{2}}^{\text{o}}}{\text{C}}$$, What is the molar mass of liquid?

A7.975 g/mol
B166 g/mol
C145.8 g/mol
Correct Answer
DNone of these

Solution

For two immiscible liquid ;
$$P_{A}^{\circ }P_{total}$$ $$P_{H_2O}^{\circ }= 748 - 648 \Rightarrow 100$$

$$\frac{W_A}{W_B}= \frac{P_{A}^{\circ }M_A}{P_{B}^{\circ }M_B}$$ : $$M_A = \frac{1.25}{1}\times \frac{648 \times 18}{100}$$

$$\Rightarrow 145.8$$

SIMILAR QUESTIONS

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