Nuclear Physics
If the series limit wavelength of Lyman series for the hydrogen atom is $$912\overset {\circ}{A}$$, then the series limit wavelength for Balmer series of hydrogen atoms is
If the radius of first Bohr's orbit is $$x$$, then de Broglie wavelength of electrons in $$^{rd}$$ orbit is nearly :
If the series limit wavelength of Lyman series for the hydrogen atom is $$912\overset {\circ}{A}$$, then the series limit wavelength for Balmer series of hydrogen atoms is
If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits a photon of wavelength $$\lambda$$. When it jumps from the 4th orbit to the 3rd orbit, the corresponding wavelength of the photon will be
The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is
Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is
In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:
The wavelengths of $$K_\alpha$$ X-rays for lead isotopes $$Pb^{208}, Pb^{206}$$ and $$Pb^{204}$$ are $$\lambda_1, \lambda_2$$ and $$\lambda_3$$ respectively. Then
Black holes in orbit around a normal star are detected from the earth due to the frictional heating of infalling gas into the black hole, which can reach temperatures greater than $$10^6K$$.Assuming that the infalling gas can be modelled as a black body radiator, then the wavelength of maximum power lies
The series corresponding to minimum wave length transition in H-atom is
Balmer gives an equation for wavelength of visible radiation of H spectrum as $$\lambda = \dfrac{kn^2}{n^2 - 4}$$. The value of k in terms of Rydberg's constant R is
The wavelength of an electron for transition from a state $$n_{1}$$ to $$n_{2}$$ is $$\displaystyle\frac{9}{8R}$$. Which of the following wavelengths is possible for a transition from $$n_{2}$$ to $$n_{1}$$