In a survey, it was fond that $$65$$% of the people watched news on TV, $$40$$% read in newspaper, $$25$$% read newspaper and watched TV. What percentage of people neither watched TV nor read newspaper?
n(Watch new on TV) $$=65\%=n(T)$$
n(Reads newspaper) $$=40\%=n(N)$$
n(Watch news on TV & read newspapers ) $$=25\%=n(T\cap N)$$
$$n(N \cup T)= n(T)+n(N)-n(N\cap T)$$
$$n(N \cup T)= 65+40-25 = 80\%$$
$$n(N\cap T)^{c}=100-80=20\%$$
Out of 800 boys in a school 224 played cricket, 240 played hockey and 236 played basketball. Of the total 64 played both basketball and hockey, 80 played cricket and basketball and 40 played cricket and hockey, 24 players all the three games. The number of boys who did not play any game is
If A and B are disjoint then $$\displaystyle \left ( A\cap B \right ){}'=$$_______
In a survey, it was fond that $$65$$% of the people watched news on TV, $$40$$% read in newspaper, $$25$$% read newspaper and watched TV. What percentage of people neither watched TV nor read newspaper?