Single Choice

Oxidation state of nitrogen is incorrectly given in:

ACompound- $$[Co(NH_3)_5Cl]Cl_2$$, Oxidation state- $$-3$$
BCompound- $$NH_2OH$$, Oxidation state- $$-1$$
CCompound- $$(N_2H_5)_2SO_4$$, Oxidation state- $$+2$$
Correct Answer
DCompound- $$Mg_3N_2$$, Oxidation state- $$-3$$

Solution

1.$$[Co(NH_3)_5Cl]Cl_2$$
Let oxidation number of $$N=x$$
Oxidation number of $$NH_3=0$$
$$x+1(3)=0$$
$$x= -3$$ is correct.

2.$$NH_2OH$$
Let oxidation number of $$N$$ $$=x$$
Oxidation number of $$H$$ $$=+1$$
Oxidation number of $$O$$ $$=-2$$
$$x+3(+1)+(-2)=0$$
$$x=-1 $$ is correct

3.$$(N_2H_5)_2SO_4$$
Let oxidation number of $$N=x$$
Oxidation number of $$H=+1$$
Oxidation number of $$SO_4$$ $$=-2$$
$$2(2(x)+5(+1))+(-2)=0$$
$$x= -2$$ is incorrect

4.$$Mg_3N_2$$
Let oxidation number of $$N=x$$
Oxidation number of $$Mg=+2$$
$$2(x)+3(+2)=0$$
$$x=-3$$ is correct

Hence, option C is the answer.

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