Single Choice

Which compound is zero valent metal complex?

A$$[Cu(NH_3)_4] SO_4$$
B$$[Pt(NH_3)_2 Cl_2]$$
C$$[Ni(CO)_4]$$
Correct Answer
D$$K_3 [Fe(CN)_6]$$

Solution

(a) $$[Cu(NH_3)_4] SO_4$$
Oxidation numbers of $$Cu$$:
$$x + 4 \times 0 - 2 = 0$$
$$x - 2 = 0$$
$$x = +2$$


(b) Oxidation number of $$Pt$$ in $$[Pt(NH_3)_2 Cl_2]$$
$$x + 2 \times 0 + 2 \times - 1 = 0$$
$$x - 2 = 0$$
$$x = +2$$


(c) Oxidation number of $$Ni$$ in $$[Ni (CO)_4]$$
$$x + 4 \times 0 = 0$$
$$x = 0$$


(d) Oxidation number of $$Fe$$ in $$K_3[Fe(CN)_6]$$
$$3 \times (+1) + x + 6 \times - 1 = 0$$
$$3 + x - 6 = 0$$
$$x = +3$$


$$\therefore [Ni(CO)_4]$$ is a zero-valent compound.

Hence, option $$C$$ is correct.

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