Physical World
The number of optically active products obtained from the complete ozonolysis of the given compound is
Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of:
Compound must be −C=CH2 group in order to give formaldehyde as one of the products.
C|RH=CH2→RCH=O+HCHOformaldehyde
Hence, option (B) is the correct answer.
The number of optically active products obtained from the complete ozonolysis of the given compound is
The olefin which on ozonolysis gives $${ CH }_{ 3 }{ CH }_{ 2 }CHO$$ and $${ CH }_{ 3 }CHO$$ is :
What reagent is used to convert the ozonide to final products of ozonolysis?
An alkene A $$\left ( C_{10}H_{20} \right )$$ on oxidative ozonolysis yields two molecules of $$\left ( C_{5}H_{10}O \right )$$ B. B on treatment with $$LiAIH_{4}$$ yields C $$\left ( C_{5}H_{12}O \right )$$ which can't be resolved into enantiomers. Which of following is correct?
Write the structural formulae of the compounds that are formed on reductive ozonolysis of: Butan-2-one + Butan-2-one
Compound 'A' on chlorination gives compound 'B', compound 'B' reacts with alc. KOH gives gas 'C', which decolourizes Baeyer's reagent and ozonolysis of compound 'C' gives only HCHO compound. Then compound 'A' is:
A hydrocarbon $$C_6H_{10}$$ absorbs only one molecule of $$H_2$$ on catalytic hydrogenation. On ozonolysis, the hydrocarbon yields $$CHO(CH_2)_4CHO$$. The hydrocarbon is:
Which compounds would give 5-keto-2-methyl hexanal upon ozonolysis?
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of $$44u$$. The alkene is:
Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of: