Single Choice

Pair of species having identical shapes for molecules is:

A$$CF_{4}, SF_{4}$$
B$$BF_{3}, PCl_{3}$$
C$$XeF_{2}, CO_{2}$$
Correct Answer
D$$PF_{5}, IF_{5}$$

Solution

Ans $$C$$ is correct.
$$XeF_2$$ and $$CO_2\Rightarrow $$ Both linear
So this option is correct.

SIMILAR QUESTIONS

Chemical Bonding

The hybridisation of carbon in diamond, graphite and acetylene are respectively:

Chemical Bonding

The hybridisation of the central atom in the following species are respectively:$$[Ni (CN)_4]^{2-},\, XeO_4,\, SF_4\,$$ and $${NO_3}^-$$

Chemical Bonding

An octahedral complex is formed when hybrid orbitals of the following types are involved:

Chemical Bonding

Which type of hybridization Is shown by carbon atoms from left to right in the given compound? $${CH_2 = CH - C \equiv N}$$

Chemical Bonding

Whay is that $$SF_4$$ molecule , the lone pair of $$e^{\circleddash }$$. occupy equatorial positions in preference to axial position? What is the shape of the molecule.

Chemical Bonding

The species in which the N atom is in a state of sp hybridization is :

Chemical Bonding

The hybridization of orbitals of $${N}$$ atom in $${N}{O}_{3}^{-},\ {N}{O}_{2}^{+}$$ and $${N}{H}_{4}^{+}$$ are respectively:

Chemical Bonding

In which of the following molecules S atom does not assume $$\displaystyle { sp }^{ 3 }$$ hybridsation?

Chemical Bonding

Which of the following organic compounds has same hybridization as its combustion product, $$CO_2$$?

Chemical Bonding

Among the triatomic molecules/ions, $$\displaystyle BeCl_{2},\ {N_{3}}^{-},\ N_{2}O,\ NO_{2}^{+},\ O_{3},\ SCl_{2},\ {ICl_{2}}^{-},\ {I_{3}}^{-}$$ and $$\displaystyle XeF_{2},$$ the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the d-orbital(s) is [Atomic number : $$S = 16, Cl = 17,I=53$$ and $$Xe = 54 ]$$

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