Subjective Type

Whay is that $$SF_4$$ molecule , the lone pair of $$e^{\circleddash }$$. occupy equatorial positions in preference to axial position? What is the shape of the molecule.

Solution

$$\displaystyle S$$ atom in $$\displaystyle SF_4$$ molecule has 4 bond pairs and one lone pair of electrons. Electron pair geometry is trigonal bipyramidal and molecular geometry is see-saw. The lone pair of electron occupies equatorial position preferentially as it gets less repulsion with bond pair of electrons.
If the lone pair of electrons is in equatorial position, then it forms an angle of approximately $$\displaystyle 120^o$$ with equatorial bond pair of electrons. But if the lone pair of electrons is in axial position, then it forms an angle of approximately $$\displaystyle 90^o$$ with equatorial bond pair of electrons. Greater is the bond angle, lesser is the repulsion between lone pair and bond pair of electrons.

SIMILAR QUESTIONS

Chemical Bonding

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Chemical Bonding

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Chemical Bonding

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Chemical Bonding

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Chemical Bonding

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Chemical Bonding

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Chemical Bonding

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Chemical Bonding

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Chemical Bonding

Which of the following organic compounds has same hybridization as its combustion product, $$CO_2$$?

Chemical Bonding

Among the triatomic molecules/ions, $$\displaystyle BeCl_{2},\ {N_{3}}^{-},\ N_{2}O,\ NO_{2}^{+},\ O_{3},\ SCl_{2},\ {ICl_{2}}^{-},\ {I_{3}}^{-}$$ and $$\displaystyle XeF_{2},$$ the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the d-orbital(s) is [Atomic number : $$S = 16, Cl = 17,I=53$$ and $$Xe = 54 ]$$

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