Subjective Type

Solve the following equation: $$x^{3} + 63x - 316 = 0$$.

Solution

Given equation, $$x^3+63x-316=0$$

$$\implies x^3 + 4x^2 - 4x^2 + 79x -16x - 316 = 0 \implies (x-4)(x^2+4x+79) = 0 $$

Solving the quadratic equation, we have $$x = -2\pm5\sqrt{3}i$$

$$\therefore\,\,$$ Roots of the given equation are $$x = 4, -2\pm5\sqrt{3}i $$

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