Single Choice

The correct order for acid strength of compounds $$CH\equiv CH, CH_{3}-C \equiv CH$$ and $$CH_{2} = CH_{2}$$ is as follows:

A$$CH \equiv CH > CH_{2} = CH_{2} > CH_{3} - C \equiv CH$$
B$$HC\equiv CH > CH_{3} - C \equiv CH > CH_{2} = CH_{2}$$
Correct Answer
C$$CH_{3} - C \equiv CH > CH_{2} = CH_{2} > HC \equiv CH$$
D$$CH_{3} - C \equiv CH > CH\equiv CH > CH_{2} = CH_{2}$$

Solution

$$CH\equiv CH > CH_{3} - C \equiv CH > CH_{2} = CH_{2}$$
(Acidic strength order).
More is the s-character, more is the acidic strength.
The s-character is maximum in $$sp$$ hybrid carbon atom followed by $$sp^2$$ and $$sp^3$$.

SIMILAR QUESTIONS

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