Single Choice

The dimensional formula of Planck's constant is:

A$$[ML^2T^{-1}]$$
Correct Answer
B$$[ML^2T^{-2}]$$
C$$[ML^0T^{2}]$$
D$$[MLT^{2}]$$

Solution

Energy of photon is given as
$$E=h\nu$$
$$\implies h=\dfrac{E}{\nu}$$
Dimension of $$E=[ML^2T^{-2}]$$
Dimension of $$\nu$$ is $$[T^{-1}]$$
Thus the dimension of plank's constant $$h$$ is $$[ML^2T^{-1}]$$

SIMILAR QUESTIONS

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