Single Choice

The relation between $$[\in_0]$$ and $$[\mu_0]$$ is

A$$[\mu_0] = [\in_0] [L]^2[T]^{-2}$$
B$$[\mu_0] = [\in_0] [L]^{-2}[T]^{2}$$
C$$[\mu_0] = [\in_0]^{-1} [L]^2[T]^{-2}$$
D$$[\mu_0] = [\in_0]^{-1} [L]^{-2}[T]^{2}$$
Correct Answer

Solution

We have,
$$C = \dfrac{1}{\sqrt{\mu_0 \in_0}}$$

$$\therefore [C^2] = \left[\dfrac{1}{\mu_0 \in_0}\right]$$

$$\Rightarrow L^2T^{-2} = \dfrac{1}{[\mu_0][\in_0]}$$

$$[\mu_0] = [\in_0]^{-1} [L]^{-2} [T]^2$$

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