The foot of the perpendicular from the point $$(3, 4)$$ on the line $$3x-4y+5=0$$ is:
If the foot of perpendicular is $$(a,b)$$, then $$3a-4b+5=0$$..(1)
Now equation of line passing through the point $$(3,4)$$ and perpendicular to given line is,
$$y-4=-\dfrac{4}{3}(x-3)\Rightarrow 4x+3y-24=0$$
Also the point $$(a,b)$$ will satisfy above line
$$4a+3b-24=0$$.......(2)
Now solving (1) and (2) we get $$a=\dfrac{81}{25}, b=\dfrac{92}{25}$$
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