The magnetic moment of the current carrying loop shown in the figure is equal is :
The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is $$B_1$$. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $$B_2$$. The ratio $$\displaystyle\frac{B_1}{B_2}$$ is?
A current carrying small loop behaves like a small magnet. If $$A$$ be its area and $$M$$ its magnetic moment, the current in the loop will be
A loop carrying current $$I$$ lies in the $$ x$$-$$y$$ plane as shown in the figure. The unit vector $$\hat{k}$$ is coming out of the plane of the paper. The magnetic moment of the current loop is
When a current in a circular loop is equivalently replaced by a magnetic dipole
A circular loop carrying a current is replaced by an equivalent magnetic dipole. A point on the loop is in
A magnetic wire of dipole moment $$4\pi$$ $$Am^2$$ is bent in the form of semi-circle. The new magnetic moment is?
Inside a long solenoid wounded with $$300$$ turns/ metre, an iron rod is placed. An iron rod is $$0.2\ m$$ long, $$10\ mm$$ in diameter and of permeability $$10^3$$. The magnetic moment of the rod, if $$0.5\ amp$$ of current is passed through the rod, is :
The value of $$\dfrac{\delta B_x}{\delta x}+\dfrac{\delta B_y}{\delta y}+\dfrac{\delta B_z}{\delta z}$$ is :
A wire of length $$L\ m$$ carrying a current $$I$$ amp is bent in the from of a circle. The magnitude of magnetic moment is :
The magnitude of magnetic moment of the current loop in the figure is :