When a current in a circular loop is equivalently replaced by a magnetic dipole
Magnetic moment is the product of pole strength and the distance between the poles.
If the loop is replaced by an equivalent magnetic dipole, the product md is fixed.
The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is $$B_1$$. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $$B_2$$. The ratio $$\displaystyle\frac{B_1}{B_2}$$ is?
A current carrying small loop behaves like a small magnet. If $$A$$ be its area and $$M$$ its magnetic moment, the current in the loop will be
A loop carrying current $$I$$ lies in the $$ x$$-$$y$$ plane as shown in the figure. The unit vector $$\hat{k}$$ is coming out of the plane of the paper. The magnetic moment of the current loop is
A circular loop carrying a current is replaced by an equivalent magnetic dipole. A point on the loop is in
A magnetic wire of dipole moment $$4\pi$$ $$Am^2$$ is bent in the form of semi-circle. The new magnetic moment is?
Inside a long solenoid wounded with $$300$$ turns/ metre, an iron rod is placed. An iron rod is $$0.2\ m$$ long, $$10\ mm$$ in diameter and of permeability $$10^3$$. The magnetic moment of the rod, if $$0.5\ amp$$ of current is passed through the rod, is :
The value of $$\dfrac{\delta B_x}{\delta x}+\dfrac{\delta B_y}{\delta y}+\dfrac{\delta B_z}{\delta z}$$ is :
A wire of length $$L\ m$$ carrying a current $$I$$ amp is bent in the from of a circle. The magnitude of magnetic moment is :
The magnetic moment of the current carrying loop shown in the figure is equal is :
The magnitude of magnetic moment of the current loop in the figure is :