Single Choice

The most basic hydroxide from following is?

A$$Pr(OH)_3(Z=59)$$
B$$Sm(OH)_3(Z=62)$$
C$$Ho(OH)_3(Z=67)$$
D$$La(OH)_3(Z=57)$$
Correct Answer

Solution

$$La(OH)_3$$ is most basic due to lanthanoid contraction. Due to lanthanoid contraction, the basicity of hydroxides decreases from $$La(OH)_3$$ to $$Lu(OH)_3$$.


Hence, the correct option is $$D$$.

SIMILAR QUESTIONS

d - block and f - block Elements

Separation of lanthanides from their mixture is not easy because of:

d - block and f - block Elements

Which of the following statements is not correct?

d - block and f - block Elements

What is the expression for the covalent radius of the following? Zr _____ Hf

d - block and f - block Elements

Reason of lanthanoid contraction is:

d - block and f - block Elements

The extent of actinoid contraction is greater than lanthanoid contraction explain.

d - block and f - block Elements

The pair that has similar atomic radii is :

d - block and f - block Elements

Because of lanthanoid contraction, which of the following pairs of elements have nearly the same atomic radii?

d - block and f - block Elements

What is meant by lanthanoid contraction? The actinoid contraction is grater than that of lanthanoid contraction. Why ?

d - block and f - block Elements

The separation of Lanthanoid elements is difficult. Explain.

d - block and f - block Elements

Which of the following factor may be regarded as the main cause of lanthanide contradiction?

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