Single Choice

To a Daniel cell, if $$CuSO_{4}$$ is added to the right hand side half cell, then the cell $$EMF$$:

Aincreases
Correct Answer
Bdecreases
Cdoes not change
Dfirst increases and then decreses

Solution

The reduction potential of cathode is directly proportional to the concentration of the electrolyte. When copper sulfate is added to the solution present in the cathode compartment, the concentration of the solution increases. This increases the reduction potential of cathode. Hence, the $$EMF$$ of the cell increases as $$CuSO_4$$ is added. $$ { E }_{ cell }\quad =\quad { E }_{ cathode }\quad -\quad { E }_{ anode } $$. Hence, option $$A$$ is correct.

SIMILAR QUESTIONS

Electrochemistry

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Electrochemistry

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Electrochemistry

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Electrochemistry

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Electrochemistry

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Electrochemistry

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Electrochemistry

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Electrochemistry

For the cell reaction, $$2{ Ce }^{ 4+ }+Co\rightarrow 2{ Ce }^{ 3+ }+{ Co }^{ 3+ }$$; $${ E }_{ cell }^{ o }$$ cell is $$1.89 V$$. If $${ E }_{ { Co }^{ 3+ }/Co }$$ is $$-0.28 V$$, what is the value of $${ E }_{ { { Ce }^{ 4+ } }/{ { Ce }^{ 3+ } } }^{ o }$$ ?

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