Two magnets of moments $$8$$ and $$125$$ units are placed so as to have a common axial line and like poles faing each other. Then the distances of the centres of the magnets from the null point will be :
Let the distances of the centers of the magnets from the null point are $$x$$ and $$y$$ respectively.
The magnetic fields are given as,
$${B_1} = {B_2}$$
$$\dfrac{{{\mu _0}}}{{4\pi }} \times \dfrac{{2{M_1}}}{{{x^3}}} = \dfrac{{{\mu _0}}}{{4\pi }} \times \dfrac{{2{M_2}}}{{{y^3}}}$$
$$\dfrac{{{\mu _0}}}{{4\pi }} \times \dfrac{{2 \times 8}}{{{x^3}}} = \dfrac{{{\mu _0}}}{{4\pi }} \times \dfrac{{2 \times 125}}{{{y^3}}}$$
$$\dfrac{x}{y} = \dfrac{2}{5}$$
Thus, the ratio of distances of the centers of the magnets from the null point is $$2:5$$.
A bar magnet of length $$l$$, pole strength $$p$$ and magnetic moment $$'\overset{\rightarrow}m '$$ is split $$l/2$$ into two equal pieces each of length. The magnetic moment and pole strength of each piece is respectively _______ and _____
A magnetised wire of moment M is bent to form an arc. The arc subtends an angle of $$60^0$$ at the centre of curvature. The new magnetic moment of the wire is:
A magnetised wire of moment M is bent to form an arc. The arc subtends an angle of $$60^0$$ at the centre of curvature. The new magnetic moment of the wire is: