Single Choice

A magnetised wire of moment M is bent to form an arc. The arc subtends an angle of $$60^0$$ at the centre of curvature. The new magnetic moment of the wire is:

A$$3M/\pi$$
Correct Answer
B$$M/ \pi$$
C$$2M / \pi$$
D$$3\sqrt3M/ \pi$$

Solution

New magnetic moment,
$$M'=M \times \dfrac{2 sin(\theta/2)}{\theta}= M \times \dfrac{2\times (1/2)}{\pi /3} = \dfrac{3M}{\pi}$$


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A magnetised wire of moment M is bent to form an arc. The arc subtends an angle of $$60^0$$ at the centre of curvature. The new magnetic moment of the wire is:

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