Which of the following is the new row that results when you add rows $$1$$ and $$3$$? $$\begin{bmatrix}3&4&2&11\\9&1&0&0\\0&1&0&2\\0&0&6&1\end{bmatrix}$$
Given Matrix$$=\begin{bmatrix} 3 & 4 & 2 & 11 \\ 9 & 1 & 0 & 0 \\ 0 & 1 & 0 & 2 \\ 0 & 0 & 6 & 1 \end{bmatrix}$$
Row $$1=\begin{bmatrix} 3 & 4 & 2 & 11 \end{bmatrix}$$
Row $$3=\begin{bmatrix} 0 & 1 & 0 & 2 \end{bmatrix}$$
Sum$$=\begin{bmatrix} 3+0 & 4+1 & 2+0 & 11+2 \end{bmatrix}$$
$$\begin{bmatrix} 3 & 5 & 2 & 13 \end{bmatrix}$$
$$\therefore $$Option $$2$$ is correct
If $$I=I=\left[ \begin{matrix} 1 \\ 0 \end{matrix}\begin{matrix} 0 \\ 1 \end{matrix} \right] ,j=\left[ \begin{matrix} 0 \\ -1 \end{matrix}\begin{matrix} 1 \\ 0 \end{matrix} \right] and B=\left[ \begin{matrix} cos\theta \\ -sin\theta \end{matrix}\begin{matrix} sin\theta \\ cos\theta \end{matrix} \right] ,$$ then B =
Apply the elementary transformation of the following matrix. $$ B = \begin{bmatrix} 1 & -1 & 3 \\ 2 & 5 & 4 \end{bmatrix}, R_{1} \rightarrow R_{1} - R_{2} $$
Find the inverse of the matrix $$A=\begin{bmatrix} 1 & 3 & 3 \\ 1 & 4 & 3 \\ 1 & 3 & 4 \end{bmatrix}$$ by using column transformations.
Find inverse, by elementary row operations (if possible), of the following matrices $$\begin{bmatrix} 1 & -3 \\ -2 & 6 \end{bmatrix}$$
If $$A = \begin{bmatrix} 1 & -1 & 0 \\ 2 & 5 & 3 \\ 0 & 2 & 1 \end{bmatrix} $$ find $$A^{-1}$$, using elementary row transformations.