Multiple Choice

Which of the following metal(s) in liquid $$NH_{3} $$ with low conc. is not paramagnetic ?

ACs
BBe
Correct Answer
CK
DMg
Correct Answer

Solution

Due to high ionization energy and metallic lattice energy Be and Mg do not dissolve into liquid $$NH_{3}$$; hence their solution in liquid $$NH_{3} $$ is not paramagnetic.

Hence, Options "B" & "D" are the correct answers.

SIMILAR QUESTIONS

s - block Elements (Alkali and Alkaline Earth Metals)

A solution of sodium metal in liquid ammonia acts as a strong reducing agent due to the presence of:

s - block Elements (Alkali and Alkaline Earth Metals)

Unreacted sodium metal can be removed from liquid ammonia safely by:

s - block Elements (Alkali and Alkaline Earth Metals)

Highly pure dilute solution of sodium in liquid ammonia :

s - block Elements (Alkali and Alkaline Earth Metals)

When an alkali metal dissolves in liquid ammonia the solution can acquire different colours. Explain the reasons for this type of colour change.

s - block Elements (Alkali and Alkaline Earth Metals)

The alkali metals dissolve in ammonia to give a deep blue solution which is conducting in nature. $$M +(x + y) NH_3 \rightarrow [M(NH_3)_x]^{2+} + 2[e(NH_3)y]^-$$ Which of the following is not true about the solutions are alkali metals in liquid ammonia?

s - block Elements (Alkali and Alkaline Earth Metals)

Select the correct statement(s):

s - block Elements (Alkali and Alkaline Earth Metals)

The alkali metals dissolve in liquid $$NH_3$$, it is found that :

s - block Elements (Alkali and Alkaline Earth Metals)

A solution of sodium in liquid ammonia is blue in colour due to:

s - block Elements (Alkali and Alkaline Earth Metals)

Which of the following statement about solution of alkali metals in liquid ammonia is correct ?

s - block Elements (Alkali and Alkaline Earth Metals)

Ammoniated solutions of alkali metals are reducing agents due to the presence of free ammoniated or solvated electrons that can reduce: (I) $$O_{2} $$ to $$O_{2}^{2-} $$ (II) $$K_{2} [Ni(AN)_4] $$ to $$K_{4} [Ni(CN)_4] $$ (III) Aromatic ring (IV) Non-terminal alkyne Choose the correct code:

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