Single Choice

A 1.24 M aqueous solution of KI has density of $$1.15 g / cm^{3}$$ . What is the percentage composition of solute in the solution?

A$$17.89$$
Correct Answer
B$$27.89$$
C$$37.89$$
D$$47.89$$

Solution

1.24 M aqueous solution of KI means 1.24 moles of KI in 1 litre of solution.

Given,
Density of solution $$= 1.15\ \dfrac{g}{cm^3}$$

Volume of solution $$= 1\ L\ or\ 1000\ cm^3$$

$$\therefore$$ Mass of solution $$= Density\times volume$$

$$= 1.15\times 1000$$

$$= 1150\ g$$

Mass of solute $$= 1.24\times 166 = 205.8\ g$$

Percentage composition of solute $$= \dfrac{\text{Mass of solute}}{\text{ Mass of solution}}\times 100$$

$$= \dfrac{205.8}{1150}\times 100$$

$$= 17.89\%$$

Hence, option A is correct.

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