Single Choice

The mole fraction of solute in aqueous urea solution is $$0.2$$. The mass percent of solute is:

A$$45.45\%$$
Correct Answer
B$$43.34\%$$
C$$34.23\%$$
D$$35.67\%$$

Solution

The mole fraction of urea is $$0.2$$.

The mole fraction of water is $$1-0.2=0.8$$.

The molar masses of urea and water are $$60$$ g/mol and $$18$$ g/mol respectively.

Let us say one mole of the total solution is present.

The number of moles of urea and water present will be $$0.2$$ mol and $$0.8$$ mol. Their masses will be $$0.2 \times 60 = 12$$ g urea and $$0.8 \times 18=14.4$$ g water.

The mass percentage of solution $$= \dfrac {Mass\ of \ urea} {Total \ mass\ of\ solution} = \dfrac {12} {12+14.4} \times 100=45.45$$ %.


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